擅长:python、mysql、java
<p>使用<code>str.join</code>:</p>
<pre><code>>>> lis = ["/x01", "/x30", "/x30", "/x53", "/x46", "/x46", "/x46", "/x30", "/x30", "/x30", "/x31", "/x46", "/x46", "/x0D"]
>>> ''.join(lis)
'/x01/x30/x30/x53/x46/x46/x46/x30/x30/x30/x31/x46/x46/x0D'
</code></pre>
<p>看看你的代码,我想你是在尝试对列表的<code>str.replace</code>应用<code>str</code>版本。但这样做会很奇怪,最好使用<code>str.join</code>:</p>
^{pr2}$
<p>上面的字符串只是list对象的一个表示。在</p>
<pre><code>>>> str(lis).replace("[","").replace("]","").replace(" ","").replace(",","").replace("'","")
'/x01/x30/x30/x53/x46/x46/x46/x30/x30/x30/x31/x46/x46/x0D'
</code></pre>