<p>我想检查一个无限数量的自我生成的网址的有效性,如果有效的安全主体的响应在一个文件。URL看起来是这样的:<a href="https://mydomain.com/" rel="nofollow">https://mydomain.com/</a>+随机字符串(例如<a href="https://mydomain.com/ake3t" rel="nofollow">https://mydomain.com/ake3t</a>),我想用字母表“abcdefghijklmnopqrstuvwxyz0123456789”生成它们,然后用暴力尝试所有可能的方法。在</p>
<p>我用python编写了一个脚本,但由于我是一个绝对的初学者,它非常慢!因为我需要的东西非常快,所以我试着用了,因为我认为它是专门为这种工作。在</p>
<p>现在的问题是我不知道如何动态地生成url,我不能预先生成它们,因为它不是固定数量的url。在</p>
<p>有人能告诉我如何做到这一点,或者向我推荐另一种更适合这项工作的工具或库吗?在</p>
<p>更新:
这是我用的脚本,但我觉得它很慢。最让我担心的是,如果我使用多个线程(在threadsNr中指定),它会变慢</p>
<pre><code>import threading, os
import urllib.request, urllib.parse, urllib.error
threadsNr = 1
dumpFolder = '/tmp/urls/'
charSet = 'abcdefghijklmnopqrstuvwxyz0123456789_-'
Url_pre = 'http://vorratsraum.com/'
Url_post = 'alwaysTheSameTail'
# class that generate the words
class wordGenerator ():
def __init__(self, word, charSet):
self.currentWord = word
self.charSet = charSet
# generate the next word set that word as currentWord and return the word
def nextWord (self):
self.currentWord = self._incWord(self.currentWord)
return self.currentWord
# generate the next word
def _incWord(self, word):
word = str(word) # convert to string
if word == '': # if word is empty
return self.charSet[0] # return first char from the char set
wordLastChar = word[len(word)-1] # get the last char
wordLeftSide = word[0:len(word)-1] # get word without the last char
lastCharPos = self.charSet.find(wordLastChar) # get position of last char in the char set
if (lastCharPos+1) < len(self.charSet): # if position of last char is not at the end of the char set
wordLastChar = self.charSet[lastCharPos+1] # get next char from the char set
else: # it is the last char
wordLastChar = self.charSet[0] # reset last char to have first character from the char set
wordLeftSide = self._incWord(wordLeftSide) # send left site to be increased
return wordLeftSide + wordLastChar # return the next word
class newThread(threading.Thread):
def run(self):
global exitThread
global wordsTried
global newWord
global hashList
while exitThread == False:
part = newWord.nextWord() # generate the next word to try
url = Url_pre + part + Url_post
wordsTried = wordsTried + 1
if wordsTried == 1000: # just for testing how fast it is
exitThread = True
print( 'trying ' + part) # display the word
print( 'At URL ' + url)
try:
req = urllib.request.Request(url)
req.addheaders = [('User-agent', 'Mozilla/5.0')]
resp = urllib.request.urlopen(req)
result = resp.read()
found(part, result)
except urllib.error.URLError as err:
if err.code == 404:
print('Page not found!')
elif err.code == 403:
print('Access denied!')
else:
print('Something happened! Error code', err.code)
except urllib.error.URLError as err:
print('Some other error happened:', err.reason)
resultFile.close()
def found(part, result):
global exitThread
global resultFile
resultFile.write(part +"\n")
if not os.path.isdir(dumpFolder + part):
os.makedirs(dumpFolder + part)
print('Found Part = ' + part)
wordsTried = 0
exitThread = False # flag to kill all threads
newWord = wordGenerator('',charSet); # word generator
if not os.path.isdir(dumpFolder):
os.makedirs(dumpFolder)
resultFile = open(dumpFolder + 'parts.txt','a') # open file for <a href="https://www.cnpython.com/list/append" class="inner-link">append</a>
for i in range(threadsNr):
newThread().start()
</code></pre>