将键与单个字典的公共值合并的python方法

Question

如何将字典中具有公共值的键合并到元组中。例如：

A = {'E2': {'5', '7'}, 'E3': {'4', '8'}, 'E5': {'5', '7'}, 'E8': {'4', '8'}}

output = {('E2', 'E5'): {'5', '7'}, ('E3', 'E8'): {'4', '8'}}

我的尝试：

^{pr2}$

打印：

OUTPUT =  {('E2', 'E5'): {'7', '5'}, ('E3', 'E8'): {'4', '8'}}

Answer 1

你可以试试这个：

from collections import defaultdict

A = {'E2': {'5', '7'}, 'E3': {'4', '8'}, 'E5': {'5', '7'}, 'E8': {'4', '8'}}

second_new = defaultdict(list)

for a, b in A.items():
    second_new[tuple(b)].append(a)

final_dict = {tuple(b):set(a) for a, b in second_new.items()}

输出：

^{pr2}$