用JS函数生成页面链接

Question

我正在尝试抓取这个页面和下一页的链接。https://www.chavesnamao.com.br/carros/usados/brasil/

<a href="javascript:;" onclick="goToPage(2); return false;" rel="next" title="Página 2">2</a>

指向下一页的链接是用这个goToPage()函数生成的。函数生成如下查询字符串

^{pr2}$

pg是请求的页面参数。有没有系统的方法来实现一个Rule在这些页面后面并调用一个解析函数，或者我需要硬编码一个循环来增加pg参数并每次发送请求吗？这是我的问题，我的蜘蛛在下面。在

class MySpider(CrawlSpider):

    name = 'myspider'

    start_urls = [
        'https://www.chavesnamao.com.br/carros/usados/brasil/#{%22pg%22:%221%22,%22or%22:%22%22,%22c%22:%22%22,%22e%22:%22%22,%22r%22:%2250%22,%22view%22:%22tabela%22}',
    ]

    def parse(self, response):

        #logging.warning('parse function called on %s', response.url)

        #from scrapy.shell import inspect_response
        #inspect_response(response, self)

        items = response.css('div.view ul#listagem li div a.description::attr(href)').getall()

        for item in items:
            yield scrapy.Request(
                url='{}'.format(item),
                method='GET',
                callback=self.parse_items,
                headers={'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/74.0.3729.169 Safari/537.36'}
            )

    def parse_items(self, response):

        # Crawling the item without any problem here