<p>这可能是一个很好的例子,说明何时从Python中的基本数据结构转换到类。在</p>
<p>考虑:</p>
<pre><code>values = ('2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K', 'A')
suits = ('H', 'C', 'D', 'S')
sRep = {'H':'Hearts', 'C':'Clubs', 'D':'Diamonds', 'S':'Spades'}
ranks = {'2':15, '3':3, '4':4,'5':5,'6':6,'7':7,'8':8,
'9':9, '0':10, '0':10, 'J':11, 'Q':12, 'K':13, 'A':14 }
class Card:
def __init__(self, value, suit):
value=str(value)
self.value, self.suit = value.upper(), suit.upper()
self.rSuit = sRep[suit.upper()]
self.rank = ranks[value.upper()]
def __repr__(self):
return "%s of %s" % (self.value, self.rSuit)
def __cmp__(self,other):
if self.rank > other.rank: return 1
if self.rank < other.rank: return -1
if self.value > other.value: return 1
if self.value < other.value: return -1
if self.rSuit > other.rSuit: return 1
if self.rSuit < other.rSuit: return -1
return 0
</code></pre>
<p>尝试一些卡片:</p>
^{pr2}$
<p>打印:</p>
<pre><code>A 2 of Spades beats a 4 of Diamonds
</code></pre>
<p>因为我们在类中定义了一个排序顺序,所以复杂的排序很容易,基于不同游戏的排名也很容易。在</p>
<p>以您的名片列表为例:</p>
<pre><code>a = [['3D'], ['3D', '4D', '5D'], ['4C'], ['2C'],['4C', '4D'], ['4D'], ['5D'], ['JC'], ['JC', 'JS'], ['JS']]
print sorted([Card(c[0],c[1]) for e in a for c in e])
</code></pre>
<p>印刷品:</p>
<pre><code>[3 of Diamonds, 3 of Diamonds, 4 of Clubs, 4 of Clubs, 4 of Diamonds,
4 of Diamonds, 4 of Diamonds, 5 of Diamonds, 5 of Diamonds, J of Clubs,
J of Clubs, J of Spades, J of Spades, 2 of Clubs]
</code></pre>
<p>再做一点工作,你就可以定义手和什么手胜过另一只手。在</p>
<p>您可以在经典的Python书籍《如何像计算机科学家一样思考:使用Python学习<a href="http://www.openbookproject.net/thinkcs/python/english2e/ch16.html" rel="nofollow">HERE</a>中阅读更多关于这个例子的内容</p>