擅长:python、mysql、java
<p>这个问题的经典解决方案往往是<a href="http://djangosnippets.org/snippets/1031/" rel="nofollow noreferrer">adding a ContentType to the superclass which stores the type of subclass for that instance</a>。这样,您就可以依赖于一个一致的API,该API返回相应类型的相关子类对象。在</p>