使用python从网站上获取每个产品的href

2024-10-02 12:24:35 发布

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我正在使用BeautifulGroup来获取此网页中每个产品的href:http://www.amazon.com/s/ref=nb_sb_noss_1?url=search-alias%3Daps&field-keywords=digital+camera。这些href以“keywords=digital+camera”结尾 我的代码是:

from bs4 import BeautifulSoup
import requests

url = "http://www.amazon.com/s/ref=nb_sb_noss_1?url=search-alias%3Daps&field-keywords=digital+camera"
keyword = "keywords=digital+camera"
r = requests.get(url)
data = r.text
soup = BeautifulSoup(data)
for link in soup.find_all('a'):
    href = link.get('href')
    if href is None:
        continue
    elif keyword in href:  
        print href

我没有从上面的脚本中得到任何东西,我能做些什么来修复它吗? 谢谢


Tags: comrefhttpurlfieldamazonsearchwww
1条回答
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1楼 · 发布于 2024-10-02 12:24:35

Amazon正在检测用户代理(“浏览器的名称”)并根据该值更改内容。如果在请求中添加一个用户代理,您将得到添加了“keyword=digital+camera”的字符串。否则,你不会

url ="http://www.amazon.com/s/ref=nb_sb_noss_1?url=search-alias%3Daps&field-keywords=digital+camera"
import urllib2
from bs4 import BeautifulSoup
req = urllib2.Request(url, headers={ 'User-Agent': 'Mozilla/5.0' })
html = urllib2.urlopen(req).read()
soup = BeautifulSoup(html)
links = soup.find_all('a')
for l in links:
    href = l.get('href')
    title = l.get('title', '')
    if 'Sony W800/B 20.1 MP Digital' in title:
        print(href)  # prints: http://www.amazon.com/Sony-W800-Digital-Camera-Black/dp/B00I8BIBCW/ref=sr_1_2/183-0842534-8993425?s=photo&ie=UTF8&qid=1421400650&sr=1-2&keywords=digital+camera

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