擅长:python、mysql、java
<p>您需要逐个迭代密码子(字符串片段在这里是您的朋友),并检查所有密码子的条件。在</p>
<pre><code>mutated = False # First, assume no mutation is present
for index in range(0, len(org), 3):
if n[org[index:index+3]] != n[pat[index:index+3]]:
mutated = True # Set mutation flag to True
break # Abort the loop - no point in checking any further
if mutated:
print("The patient's amino acid sequence is mutated.")
else:
print("The patient's amino acid sequence is not mutated.")
</code></pre>
<p>这假设<code>org</code>和{<cd2>}的长度相同,可以被3整除。您可能需要事先插入一个检查,以确保情况确实如此。在</p>