擅长:python、mysql、java
<p>我找到了解决办法。要在浏览器中查看url并同时查看此页面的源代码,请使用以下代码:</p>
<pre><code>from selenium import webdriver
from lxml import etree, html
url = "https://prod.ceidg.gov.pl/CEIDG/CEIDG.Public.UI/Search.aspx"
adres_prefix = "https://prod.ceidg.gov.pl/CEIDG/CEIDG.Public.UI/"
adres_sufix = etree.XPath('string(//img[@class="captcha"]/@src)')
browser = webdriver.Firefox()
browser.get(url)
html_source = browser.page_source # i'm getting source code of open url
root = etree.HTML(html_source)
result = etree.tostring(root, pretty_print=True, method="html")
result2 = adres_sufix(root)
www = adres_prefix + result2
print www # now i see if XPath gives me right value
</code></pre>
<p>希望它能帮助别人
无论如何谢谢你的帮助</p>