<p>我需要帮助如何将一个txt文件中的多行连接成一行,而不需要空格</p>
<p>文本文件由8行组成,每行有80个字符,如下所示:</p>
<p><a href="https://i.stack.imgur.com/dfoDU.jpg" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/dfoDU.jpg" alt="a busy cat"/></a><br/>
<sub>(来源:<a href="http://im33.gulfup.com/HMGw2.jpg" rel="nofollow noreferrer">gulfup.com</a>)</sub></p>
<p>下面是我使用的代码,但我的问题是,我无法将所有的行连接起来,它们之间没有空格:</p>
<pre><code>inFile = open ("text.txt","r") # open the text file
line1 = inFile.readline() # read the first line from the text.txt file
line2 = inFile.readline() # read the second line from the text.txt file
line3 = inFile.readline()
line4 = inFile.readline()
line5 = inFile.readline()
line6 = inFile.readline()
line7 = inFile.readline()
line8 = inFile.readline()
print (line1.split("\n")[0], # split each line and print it --- My proplem in this code!
line2.split("\n")[0],
line3.split("\n")[0],
line4.split("\n")[0],
line5.split("\n")[0],
line6.split("\n")[0],
line7.split("\n")[0],
line8.split("\n")[0])
</code></pre>
<p><a href="https://i.stack.imgur.com/XimDU.jpg" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/XimDU.jpg" alt="a busy cat"/></a><br/>
<sub>(来源:<a href="http://im33.gulfup.com/XfXJ1.jpg" rel="nofollow noreferrer">gulfup.com</a>)</sub></p>