类型错误：在数学方程中无法隐式地将'int'变量转换为str

Question

我对python还不熟悉，但我试着把DogAge放入一个数学方程中，仍然不起作用

Animal = input("dog or cat? ")

if Animal == "dog":
    DogAge = int(input("how old is you dog? "))
else:
    CatAge = int(input("how old is your cat? "))

if DogAge == 1:
    print("your dog's age is 11")
elif DogAge == 2:
    print("your dog's age is 22")
else:
    print("your dog's age is " + (DogAge - 2 * 4 + 22))

给出：

^{pr2}$

Answer 1

另一种解决方案：

print("your dog's age is {0}".format((DogAge - 2) * 4 + 22))

（假设您要计算(DogAge-2) * 4 + 22，而不是{}）。在

Answer 2

错误指出了出了什么问题。更改此项：

print("your dog's age is " + (DogAge - 2 * 4 + 22))

为此：

^{pr2}$

不能用整数连接字符串对象。在

Answer 3

您可能需要考虑以不同的方式重新组织代码，将计算狗的年龄和实际打印的值分开。在

因为如果代码变得更复杂，那么以后可以将代码重构为函数。在

Animal = input("dog or cat? ")

if Animal == "dog":
    DogAge = int(input("how old is you dog? "))
else:
    CatAge = int(input("how old is your cat? ")) 

if DogAge == 1:
    calculated_dogs_age = 11
elif DogAge == 2:
    calculated_dogs_age = 22
else:
    calculated_dogs_age = DogAge - 2 * 4 + 22

print("your dog's age is {0:d}".format(calculated_dogs_age))