我正在使用League of Legends API,并尝试从JSON文件中获取排名数据。但是,如果玩家不是等级30的玩家,他就没有他的档案。 所以这里
def getRankedData(region, ID, APIkey):
URL = "https://" + region + ".api.pvp.net/api/lol/" + region + "/v2.5/league/by-summoner/" + ID + "/entry?api_key=" + APIkey
response = requests.get(URL)
return response.json()
它不会得到JSON文件,因为它不存在。我该怎么做,如果URL不存在并且没有JSON文件,它将返回字符串。在
在这里,我将数据返回到HTML页面。但这也不管用。在
^{pr2}$我得到了这个错误:
Traceback (most recent call last)
File "C:\Python27\lib\site-packages\flask\app.py", line 1836, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Python27\lib\site-packages\flask\app.py", line 1820, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "C:\Python27\lib\site-packages\flask\app.py", line 1403, in handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1817, in wsgi_app
response = self.full_dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1477, in full_dispatch_request
rv = self.handle_user_exception(e)
File "C:\Python27\lib\site-packages\flask\app.py", line 1381, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1475, in full_dispatch_request
rv = self.dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1461, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "C:\Users\Hanisek\Documents\Visual Studio 2015\Projects\FlaskWebProject2\FlaskWebProject2\FlaskWebProject2\views.py", line 53, in hello
responseJSON2 = getRankedData(region, ID, APIkey)
File "C:\Users\Hanisek\Documents\Visual Studio 2015\Projects\FlaskWebProject2\FlaskWebProject2\FlaskWebProject2\views.py", line 21, in getRankedData
Open an interactive python shell in this framereturn response.json()
File "C:\Python27\lib\requests\models.py", line 805, in json
return complexjson.loads(self.text, **kwargs)
File "C:\Python27\lib\json\__init__.py", line 338, in loads
return _default_decoder.decode(s)
File "C:\Python27\lib\json\decoder.py", line 366, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
File "C:\Python27\lib\json\decoder.py", line 384, in raw_decode
raise ValueError("No JSON object could be decoded")
ValueError: No JSON object could be decoded
您可以尝试检查URL是否存在,JSON格式是否正确,或者页面是否抛出40X个状态代码
通过在浏览器中运行来检查api url返回的内容总是一个好主意。我猜它会返回404错误,因为信息不存在。在
在这种情况下,我建议在继续进行JSON解析之前检查是否存在404错误。在
请求有一个名为status_code的函数,如果有404错误,它将返回404错误。 示例代码:
不知道很多关于LOL的知识,但是有没有理由让你的程序使用和if/then语句来检查播放器的级别,然后只检查json文件,如果播放器的级别足够高,可以有一个?在
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