在python和

Question

我需要你的帮助，我写了这个函数来保存一个音频流使用vlc.py公司，但当我在终端上运行时，什么也没发生。当我使用python解释器时，我创建音频文件。谢谢

import vlc

def grabar_audio(stream, parametros):

    radio = stream
    datos = parametros
    instancia = vlc.Instance()
    player = instancia.media_player_new()
    media = instancia.media_new(radio, datos)
    media.get_mrl()
    player.set_media(media)
    player.play()

    return media

radio = 'http://212.83.146.67:7212/stream'

datos = "--sout=#standard{access=file,mux=ts,dst='/home/eparionad/Descargas/ProyectoPython/prueba32.mp3'} --run-time=10 --stop-time=10"

grabar_audio(radio, datos)

Answer 1

问题是实例是在程序运行时执行的，在示例中，您总是使用具有无限循环的GUI，但是在您的代码中，我们必须提供它。在

import sys
import vlc
from time import sleep

def grabar_audio(stream, parametros):

    radio = stream
    datos = parametros
    instancia = vlc.Instance()

    player = instancia.media_player_new()
    media = instancia.media_new(radio, datos)
    media.get_mrl()

    player.set_media(media)
    player.play()
    return media

radio = 'http://212.83.146.67:7212/stream'

datos = " sout=#standard{access=file,mux=ts,dst='/home/eparionad/Descargas/ProyectoPython/prueba32.mp3'}  run-time=10  stop-time=10"

grabar_audio(radio, datos)
while True:
    try:
        sleep(1)
    except KeyboardInterrupt:
        sys.exit(0)