擅长:python、mysql、java
<p>只能使用Etree获取输出:
如本文所述(我建议您仔细阅读本文档)<a href="https://docs.python.org/2/library/xml.etree.elementtree.html" rel="nofollow noreferrer">https://docs.python.org/2/library/xml.etree.elementtree.html</a>:<em>子节点是嵌套的,我们可以通过索引访问特定的子节点</p>
<p>所以,你可以这样做:</p>
<pre><code>for i in root[0][0][0]: # looping over CHANNELS
if 'ROTARY' in i[5].text: # if 'ROTARY' is in COMMENT
print i[4].text # print corresponding SIGNALNAME
</code></pre>