Python POST请求repsonse和JSON解析

Question

我使用Python2.7.7向网站发送post请求。Im使用requests模块，代码如下：（NAME和PASS被替换）

r = requests.post("http://play.pokemonshowdown.com/action.php", data="act=login&name=NAME&pass=PASS&challengekeyid="+challstrarr[2]+"&challenge="+challstrarr[3])

    print(r.text)
    print(r.json())

Json返回的是一个空的Json对象，错误是：一个错误

我请求的网站有以下教程：

you'll need to make an HTTP POST request to http://play.pokemonshowdown.com/action.php with the data act=login&name=USERNAME&pass=PASSWORD&challengekeyid=KEYID&challenge=CHALLENGE

Either way, the response will start with ] and be followed by a JSON object which we'll call data."

我不确定POST请求响应是否是错误的（因此是空白行），或者如果它没有错误，JSON解析是关闭

Answer 1

您应该将dictionary对象传递给post函数（data参数），只有在get方法中才应该传递查询字符串：

postData = {
#put you post data here
}
r = requests.post("http://play.pokemonshowdown.com/action.php", data=postData)
print(r.text)
print(r.json())