对pandass dataframe列使用apply/map

Question

我有熊猫的数据帧：

df.text[:3]

0    nena shot by me   httptcodcrsfqyvh httpstcokxr...
1           full version of soulless    httptcowfmcyyu
2    when youre having a good day but then get to w...
Name: text, dtype: object

基本上它只是一个系列的tweets文本。没别的了。在

^{pr2}$

现在我想在这个系列中拆分单词。它可以很好地配合这个：

df.text.str.split('')

0     [nena shot by me   httptcodcrsfqyvh httpstcokx...
1          [full version of soulless    httptcowfmcyyu]
2     [when youre having a good day but then get to ...

但是id不能用于apply方法：

df.text.apply(lambda x: x.split(' '))

并引发异常：AttributeError: 'float' object has no attribute 'split'

我做错了什么？为什么apply方法把这个int索引作为参数？在

如果我使用df.text.map(lambda x: x.split(' '))也一样

UPD公司

df[df.text == np.nan].shape
(0, 13)

以及

df.text[:3]

0    nena shot by me   httptcodcrsfqyvh httpstcokxr...
1           full version of soulless    httptcowfmcyyu
2    when youre having a good day but then get to w...

工作正常：

df.text[:3].map(lambda x: x.split())

0    [nena, shot, by, me, httptcodcrsfqyvh, httpstc...
1        [full, version, of, soulless, httptcowfmcyyu]
2    [when, youre, having, a, good, day, but, then,...
Name: text, dtype: object