擅长:python、mysql、java
<p>我想出的答案是使用re模块,并使所有字符串“原始”字符串。有关原始字符串的详细信息,请查看<a href="http://docs.python.org/reference/lexical_analysis.html" rel="nofollow">http://docs.python.org/reference/lexical_analysis.html</a></p>
<pre><code>import re
paths = [r'D:\notebook\bot', r'D:\newworld']
for p in paths:
result = re.sub(r':?\\', "/", p)
print(result)
</code></pre>