擅长:python、mysql、java
<p>lambda中:</p>
<pre><code>def make_cell(value):
fn = (lambda x: lambda: x)(value)
return fn.__closure__[0]
</code></pre>
<p>从<a href="https://github.com/nedbat/byterun/blob/master/byterun/pyobj.py#L12" rel="nofollow noreferrer">https://github.com/nedbat/byterun/blob/master/byterun/pyobj.py#L12</a>得到答案</p>