我有以下代码:
tree = etree.ElementTree(new_xml)
for e in new_xml.iter():
print tree.getpath(e), e.text
这将给我一些类似以下内容:
^{pr2}$但是,我需要的不是列表元素的路径,而是属性的路径。以下是xml的外观:
<Item>
<Purchases>
<Purchase Country="US">
<URL>http://tvgo.xfinity.com/watch/x/6091165US</URL>
<Rating>R</Rating>
</Purchase>
<Purchase Country="CA">
<URL>http://tvgo.xfinity.com/watch/x/6091165CA</URL>
<Rating>R</Rating>
</Purchase>
</Item>
我怎样才能得到下面的路径呢?在
/Item/Purchases
/Item/Purchases/Purchase[@Country="US"]
/Item/Purchases/Purchase[@Country="US"]/URL http://tvgo.xfinity.com/watch/x/6091165185315991112/movies
/Item/Purchases/Purchase[@Country="US"]/Rating R
/Item/Purchases/Purchase[@Country="CA"]
/Item/Purchases/Purchase[@Country="CA"]/URL http://tvgo.xfinity.com/watch/x/6091165185315991112/movies
/Item/Purchases/Purchase[@Country="CA"]/Rating R
不漂亮,但它能起作用。在
为我打印这个:
^{pr2}$相关问题 更多 >
编程相关推荐