以CSV格式打印前6行，然后开始读取

Question

所以我有一个CSV，我试图打印出头6行，然后在后面开始代码。我是超级新手。我知道如何用next（reader）跳过前6行，但我需要打印前5行，因为它是头，然后在数据开始的第8行启动脚本。所以我认为这是reader=后面的某种print语句，然后可能是下一个（reader）来启动代码。只是我的理论。在

import csv

with open('GAT_US_PartReview_2017-06-23.csv', newline='') as f:
    reader = csv.reader(f)



    for row in reader:
        hqline, part_no, part_class, appl_req, appl_count, intr_req, 
        intr_count, oe_intr, has_oe_intr, has_attr_editor,
        part_IMG_req, has_part_img, has_part_img, has_mpcc, warr_req, 
        warr_txt, warr_pdf, msds_req, has_msds, upc_req, has_upc, 
        has_unspsc, attr_count, attrval_count, valid_part = row

^{pr2}$

Answer 1

你为什么不试试列举？在

import csv

with open('GAT_US_PartReview_2017-06-23.csv', newline='') as f:
    reader = csv.reader(f)

    for row_num, row in enumerate(reader):
        if row_num <= 5:
            print row  # Print out the header
        else:
            hqline, part_no, part_class, appl_req, appl_count, intr_req, 
            intr_count, oe_intr, has_oe_intr, has_attr_editor,
            part_IMG_req, has_part_img, has_part_img, has_mpcc, warr_req, 
            warr_txt, warr_pdf, msds_req, has_msds, upc_req, has_upc, 
            has_unspsc, attr_count, attrval_count, valid_part = row