擅长:python、mysql、java
<p>我发现了一个更简单的解决方案,使用<code>Catenate</code>将json主体中的两个值随机化。在</p>
<pre><code>${shizzleiz}= shizzleiz # or whatever you want to appear there
${json_string}= Catenate {"elementKey":"P690-C0-C3-B1","fields":[{"key":"P690-C1-C2-C1-C1-C1-F0","values":[]},{"key":"P690-C0-C2-F8","values":["1200"]},{"key":"P690-C0-C2-F9","values":["22000"]},{"key":"P690-C0-C2-F11","values":["I"]},{"key":"P690-C0-C2-F10","values":["2200"]},{"key":"P690-C0-C2-C0-C0-F0","values":["98-zsg-2"]},{"key":"P690-C1-C0-C0-F1","values":["Personenauto"]},{"key":"P690-C1-C0-C0-F2","values":["Personenauto KVP"]},{"key":"P690-C0-C2-F6","values":["B"]},{"key":"P690-C0-C2-F7","values":["75"]},{"key":"P690-C0-C2-F4","values":["2"]},{"key":"P690-C0-C2-F5","values":["5"]},{"key":"P690-C0-C2-F2","values":["model"]},{"key":"P690-C0-C2-F3","values":["2017"]},{"key":"P690-C1-C2-C2-C2-C1-F0","values": ${shizzleiz} ${the-rest-of-the-long-json-as-a-string}
</code></pre>
<p>然后继续:</p>
^{pr2}$
<p>(基本上是在对json函数做出反应之前做这项工作——显然这需要事先知道值,还可以使用更多变量。)</p>