<p>问题是,我已经完成了代码并尝试了。这是可行的,但这不是问题的答案。从链接中获取角色并将其组合在一起是行不通的。我试了很多东西,我自己还在努力。我的建议是,你自己解决。这会有更多的回报,可能会对未来的竞争有所帮助。另外,如果你想从代码中删除所有的'a',那也行不通。我试过了。在</p>
<p>要回答堆栈溢出问题,下面是代码(您需要先安装'requests'python modeule):</p>
<pre><code>import requests
page1 = "https://assess.joincyberdiscovery.com/challenge-files/clock-pt1?verify=4VjvSgWQQ8yhhiYD9cePtg%3D%3D"
page1_content = requests.get(page1)
page1text = page1_content.text
page2 = "https://assess.joincyberdiscovery.com/challenge-files/clock-pt2?verify=4VjvSgWQQ8yhhiYD9cePtg%3D%3D"
page2_content = requests.get(page2)
page2text = page2_content.text
page3 = "https://assess.joincyberdiscovery.com/challenge-files/clock-pt3?verify=4VjvSgWQQ8yhhiYD9cePtg%3D%3D"
page3_content = requests.get(page3)
page3text = page3_content.text
page4 = "https://assess.joincyberdiscovery.com/challenge-files/clock-pt4?verify=4VjvSgWQQ8yhhiYD9cePtg%3D%3D"
page4_content = requests.get(page4)
page4text = page4_content.text
page5 = "https://assess.joincyberdiscovery.com/challenge-files/clock-pt5?verify=4VjvSgWQQ8yhhiYD9cePtg%3D%3D"
page5_content = requests.get(page5)
page5text = page5_content.text
print(page1text + page2text + page3text + page4text + page5text)
</code></pre>
<p>但是这个方法不能回答挑战14。在</p>