如何防止用户在Python中输入空格？

Question

我有一个问题，用户可以输入空格或什么都不输入，但仍然可以通过程序，我如何防止这种情况发生？我还是python的初学者。

def orderFunction(): # The function which allows the customer to choose delivery or pickup
    global deliveryPickup
    deliveryPickup = input("Please input delivery or pickup: d for delivery p for pickup")
    if deliveryPickup == "d": 
        global customerName
        while True:
            try:
                customerName = (input("Please input your name"))
                if customerName == (""):
                    print("Please input a valid name")
                else:
                    break
        global customerAddress
        while True:
            try:
                customerAddress = (input("Please input your name"))
                if customerAddress == (""):
                    print("Please input a valid Address")
                else:
                    break
        global customerPhnum
        while True: 
            try: 
                customerPhnum = int(input("Please input your phone number"))
            except ValueError:
                print("Please input a valid phone number")
            else:
                break
            print("There will also be a $3 delivery surcharge")
    elif deliveryPickup == "p": 
        customerName = (input("Please input your name"))
        if customerName == (""):
            print("Please input a valid name")
            orderFunction()

    else:
        print("Please ensure that you have chosen d for Delivery or p for Pickup")
        orderFunction()

orderFunction()   

这是我的尝试，但我得到了各种各样的无凹痕和缩进错误，我认为我的while循环可能是错误的。

本质上，如果我在其中一个客户输入（例如customerName）中输入一个空格或按enter键，它就会被存储起来。这需要防止，我已经尝试过使用while循环来修复它，但显然没有起作用。

希望有人能解决这个问题

非常感谢。

Answer 1

.strip()删除字符串前后的所有制表符或空格。 表示所有空格==空字符串。所有制表符==空字符串。所以你要检查一下绳子的长度！=0或字符串不为空。只需使用无限循环来继续强制输入正确的内容。在

作为一个提示，你不必把自己局限于一个功能。 下面是一个工作代码。在

def getNonBlankInput(message, error_message):

    x = input(message)
    while len(x.strip()) == 0:
        x = input(error_message)

    return x

def getValidIntegerInput(message, error_message):

    msg = message
    while(True):
        try: 
            x = int(input(msg))
            break
        except ValueError:
            msg = error_message

    return x


def orderFunction(): # The function which allows the customer to choose delivery or pickup
    global deliveryPickup
    global customerName
    global customerAddress
    global customerPhnum

    deliveryPickup = input("Please input delivery or pickup: d for delivery p for pickup")

    if deliveryPickup == "d": 
        customerName = getNonBlankInput("Please input your name: ", "Please input a valid name: ")
        customerAddress = getNonBlankInput("Please input your address: ", "Please input a valid address: ")
        customerPhnum = getValidIntegerInput("Please input your phone number: ", "Please input a valid phone number: ")
        print("There will also be a $3 delivery surcharge")
    elif deliveryPickup == "p": 
        customerName = getNonBlankInput("Please input your name: ", "Please input a valid name: ")
    else:
        print("Please ensure that you have chosen d for Delivery or p for Pickup")
        orderFunction()

orderFunction() 

Answer 2

如果你需要更多的checks来增加你的循环。在

首先，不需要在前两个循环上使用try语句。不要使用try语句，除非您预期出现错误，您需要使用except语句来处理，就像在bottomwhile循环中那样。在

然后你只需要给你的前两个循环添加更多的条件，我不知道你到底想阻止什么，但是你可以尝试检查输入的长度，也可以看看下面的答案，找到一个有趣的方法： https://stackoverflow.com/a/2405300/8201979

Answer 3

尝试使用一个regular expression来检查是否插入了“a-Z”之间的任何字符，如果没有，则给出一个错误