<p>好的,这是解决方案请验证,并让我知道它是否适合您:</p>
<p>我改变了一点名字来理解我自己:</p>
<pre><code>#!/usr/bin/python
table1 = ('A', 'B', 'C', 'D')
table2 = ('B', 'D', 'E')
row1 = [['A', 1, 'A', 'a'],
['B', 2, 'Y', 'a'],
['Y', 4, 'B', 'b'],
['A', 1, 'Y', 'a'],
['S', 2, 'B', 'b']]
row2 = [[1, 'a', 'A'],
[3, 'a', 'B'],
[1, 'a', 'Y'],
[2, 'b', 'S'],
[3, 'b', 'E']]
def findindices(table1, table2):
inter = set(table1).intersection(set(table2))
tup_index1 = [table1.index(x) for x in inter]
tup_index2 = [table2.index(x) for x in inter]]
return tup_index1, tup_index2
def main():
final_lol = list()
tup_index1, tup_index2 = findindices(table1, table2)
merge_tup = zip(tup_index1, tup_index2)
for tup1 in row1:
for tup2 in row2:
for m in merge_tup:
if tup1[m[0]] != tup2[m[1]]:
break
else:
ls = []
ls.extend(tup1)
ls.append(tup2[-1])
final_lol.append(ls)
return final_lol
if __name__ == '__main__':
import pprint
pprint.pprint(main())
</code></pre>
<p>输出:</p>
^{pr2}$