使用Pas部署Flask应用程序

Question

我正在使用Flask构建一个web服务，并尝试使用Paster部署一个简单的“Hello，World”应用程序。不过，我很难把所有配置好一起工作。我看过Google关于使用virtualenv和zcbuildout来运行带有paste的Flask，但是对于一个非常基本的应用程序来说，这似乎有些过头了。现在，当我试图用我的应用程序加载URL时，我收到以下错误：

Traceback (most recent call last):
File "/usr/lib/python2.7/dist-packages/paste/httpserver.py", line 1068, in process_request_in_thread
  self.finish_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 323, in finish_request
  self.RequestHandlerClass(request, client_address, self)
File "/usr/lib/python2.7/SocketServer.py", line 639, in __init__
  self.handle()
File "/usr/lib/python2.7/dist-packages/paste/httpserver.py", line 442, in handle
  BaseHTTPRequestHandler.handle(self)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 343, in handle
  self.handle_one_request()
File "/usr/lib/python2.7/dist-packages/paste/httpserver.py", line 437, in handle_one_request
  self.wsgi_execute()
File "/usr/lib/python2.7/dist-packages/paste/httpserver.py", line 287, in wsgi_execute
  self.wsgi_start_response)
AttributeError: GraffitiApp instance has no __call__ method

我的应用程序配置如下：

^{pr2}$

我的应用程序代码如下：

from flask import Flask

app = Flask(__name__)
app.debug = True

class GraffitiApp:

    @app.route('/')
    def hello_world():
        return "Hello World!"

    @app.route('/other')
    def other_page():
        return "Other page!"

    def main():
        app.run(debug = True)

if __name__ == "__main__":
    app.run(debug = True)

我需要创建一个__call__()方法并将传递给相应函数的URL映射，还是需要对配置进行更改？在

编辑

我用的是一家名为主.py由于错误，我发现找不到名为“main”的入口点：

import logging

from graffiti import GraffitiApp

def make_app(globalArgs, **localArgs):
    loglevelname = globalArgs.get("loglevel", "INFO").lower()

    if loglevelname == 'critical':
        loglevel = logging.CRITICAL
    elif loglevelname == 'debug':
        loglevel = logging.DEBUG
    elif loglevelname == 'error':
        loglevel = logging.ERROR
    elif loglevelname == 'fatal':
        loglevel = logging.FATAL
    elif loglevelname == 'info':
        loglevel = logging.INFO
    elif loglevelname == 'warn' or loglevelname == 'warning':
        loglevel = logging.WARN
    else:
        loglevel = logging.NOTSET
        loglevelname = 'notset'

    FORMAT = "%(asctime)s %(name)s %(levelname)s %(message)s"
    logging.basicConfig(format = FORMAT, level = loglevel)
    logging.info("Log level set to %s" % (loglevelname.upper()))

    return GraffitiApp()

Answer 1

OFFTOP（抱歉，你的代码让我目瞪口呆）：

import logging

from graffiti import GraffitiApp

def make_app(globalArgs, **localArgs):
    loglevelname = globalArgs.get("loglevel", "INFO")
    loglevel = getattr(logging, loglevelname.upper(), logging.NOTSET)


    FORMAT = "%(asctime)s %(name)s %(levelname)s %(message)s"
    logging.basicConfig(format = FORMAT, level = loglevel)
    logging.info("Log level set to %s" % (loglevelname))

    return GraffitiApp()

Answer 2

似乎服务器正在尝试运行您的GraffitiApp()类，而它应该运行Flask()实例app。