从文件中每隔n（8个字符）打印一次[Python]

Question

我从一个文件中转储了一长串的位。现在，我想取这个位序列，并能从中提取每8位。例如：

100010010101000001001110010001110000110100001010
000110100000101000000000000000000000000000001101
010010010100100001000100010100100000000000000000
etc

会给出：

^{pr2}$

到目前为止，我有以下代码：

 #/usr/bin/python

 with open("thebits.txt", 'r') as f:
        content = [x.strip('\n') for x in f.readlines()]
        {//logic to extract every 8th bit from each line and print it}

如何从每行中提取每8位？ . 在

Answer 1

可以使用简单切片：

with open('thebits.txt', 'r') as f:
    for line in f:
        print line.strip()[7::8]

示例文件给出了：

^{pr2}$

片[7::8]提供从第8个开始的每8个字符（从0索引的7个）。在

Answer 2

with open(infile) as f:
    print("".join(line[7::8] for line in f))

Answer 3

假设您希望每一行分开：

with open('tmp.txt', 'r') as f:
    for line in f.read().splitlines():
        print(line[7::8])