基于py小波的多级部分小波重构

2024-09-19 03:56:51 发布

您现在位置:Python中文网/ 问答频道 /正文

我在寻找一种方法来部分重建小波分解的分支,这样求和就能重新生成原始信号。这可以通过使用Matlab实现:

DATA = [0,1,2,3,4,5,6,7,8,9]
N_LEVELS = 2;
WAVELET_NAME = 'db4';
[C,L] = wavedec(DATA, N_LEVELS, WAVELET_NAME);
A2 = wrcoef('a', C, L, WAVELET_NAME, 2);
D2 = wrcoef('d', C, L, WAVELET_NAME, 2);
D1 = wrcoef('d', C, L, WAVELET_NAME, 1);
A2+D2+D1

ans =

    0.0000    1.0000    2.0000    3.0000    4.0000    5.0000    6.0000    7.0000    8.0000    9.0000

我想用pywt实现同样的效果,但我不知道该怎么做。 pywt.waverec函数创建完全重建,但没有用于部分重建的level参数。 pywt.upcoef函数可以满足单个级别的需要,但我不确定如何将其扩展到多个级别:

^{pr2}$

Tags: 方法函数namea2data信号分支级别
2条回答

我成功地编写了我自己的wrcoef函数的版本,它看起来像预期的那样工作:

import pywt
import numpy as np

def wrcoef(X, coef_type, coeffs, wavename, level):
    N = np.array(X).size
    a, ds = coeffs[0], list(reversed(coeffs[1:]))

    if coef_type =='a':
        return pywt.upcoef('a', a, wavename, level=level)[:N]
    elif coef_type == 'd':
        return pywt.upcoef('d', ds[level-1], wavename, level=level)[:N]
    else:
        raise ValueError("Invalid coefficient type: {}".format(coef_type))



level = 4
X = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17]
coeffs = pywt.wavedec(X, 'db1', level=level)
A4 = wrcoef(X, 'a', coeffs, 'db1', level)
D4 = wrcoef(X, 'd', coeffs, 'db1', level)
D3 = wrcoef(X, 'd', coeffs, 'db1', 3)
D2 = wrcoef(X, 'd', coeffs, 'db1', 2)
D1 = wrcoef(X, 'd', coeffs, 'db1', 1)
print A4 + D4 + D3 + D2 + D1

# Results:
[  9.99200722e-16   1.00000000e+00   2.00000000e+00   3.00000000e+00
   4.00000000e+00   5.00000000e+00   6.00000000e+00   7.00000000e+00
   8.00000000e+00   9.00000000e+00   1.00000000e+01   1.10000000e+01
   1.20000000e+01   1.30000000e+01   1.40000000e+01   1.50000000e+01
   1.60000000e+01   1.70000000e+01]

目前,pywt还没有实现wrcoef等价函数。但您仍然可以分解一维多电平信号,然后分别重建其分量。在

import pywt
def decomposite(signal, coef_type='d', wname='db6', level=9):
    w = pywt.Wavelet(wname)
    a = data
    ca = []
    cd = []
    for i in range(level):
        (a, d) = pywt.dwt(a, w, mode)
        ca.append(a)
        cd.append(d)
    rec_a = []
    rec_d = []
    for i, coeff in enumerate(ca):
        coeff_list = [coeff, None] + [None] * i
        rec_a.append(pywt.waverec(coeff_list, w))
    for i, coeff in enumerate(cd):
        coeff_list = [None, coeff] + [None] * i
        rec_d.append(pywt.waverec(coeff_list, w))
    if coef_type == 'd':
        return rec_d
    return rec_a

我们需要对返回值进行切片,使其与输入信号具有相同的长度。然后我们就可以得到分解后的每个组分。在

^{pr2}$

相关问题 更多 >