从SID获取用户名的pythonldap3代码

Question

我有一个共享Windows服务器上用户的SID字符串（例如，“S-1-5-21-500000003-10000000003-10000000003-1001”），我需要获取相关的用户名。在

我认为这可以通过以下方式实现： 1） 将SID字符串转换为字节数组。 2） 使用合适的ldpa查询获取相关用户名。在

但我没能找到准确可靠的操作指南。在

我将非常感谢任何有用的指南，特别是如果它附带了Python（ldap3）代码演示。在

谢谢！在

Answer 1

def unsigned_number_to_slashed_byte_array_string(number, little_endian, digits_count):
        """
        Convert given unsigned number into a string that represents it as a sequence of bytes in given order (either little or big Endian).
        In case the total number of digits in the string is greater than given digits count, the string is left-padded with zeroes.
        Each such byte is represented by a substring that's composed of a preceding slash character followed by two (uppercase) hexadecimal digits (e.g., "\\0A").
        :param number: An unsigned non-negative integer.
        :param little_endian: A flag that says whether little Endian order is requested; otherwise, big Endian order is selected.
        :param digits_count: The total count of hexadecimal digits in the resulting possibly left-padded string, which is twice the number of bytes.
        :except ValueError: In case given number isn't a non-negative number, or given digits count isn't a positive even number.
        :return: A string that represents given number as a sequence of bytes in given order.
        """
        if number < 0: raise ValueError("{0}: Argument number must be a non-negative! ({1})".format(func_name(), number))
        if (digits_count <= 0) or ((digits_count % 2) != 0): raise ValueError("{0}: Argument digits_count must be an even positive! ({1})".format(func_name(), digits_count))

        zero_padded_hex_number_str = "{0:0{1}X}".format(number, digits_count) # Format: no leading "0x", zero-padded digits_count digits (or half digits_count bytes), uppercase hexadecimal letters.
        number_byte_array_str = ""
        byte_starter_digits_indices_list = range(len(zero_padded_hex_number_str))[::2]
        if little_endian: byte_starter_digits_indices_list = reversed(byte_starter_digits_indices_list)
        for byte_starter_digit_index in byte_starter_digits_indices_list:
            number_byte_array_str = "{0}\\{1}".format(number_byte_array_str, zero_padded_hex_number_str[byte_starter_digit_index:(byte_starter_digit_index + 2)])
        return number_byte_array_str


def sid_str_to_byte_array_str(sid_str):
    """
    :param sid_str: An active-directory SID string (e.g., "S-1-5-21-1241979920-1440912824-1533017923-1106").
    :return: A string that represents given SID string as a byte array string (e.g., "\\01\\05\\00\\00\\00\\00\\00\\05\\15\\00\\00\\00\\10\\1C\\07\\4A\\B8\\95\\E2\\55\\43\\FF\\5F\\5B").
    """
    dashes_count = sid_str.count("-")
    sid_numbers_str = sid_str[2:] # Removes the preceding "S-"
    sid_number_strings = sid_numbers_str.split("-")
    sid_numbers = [int(sid_number_string) for sid_number_string in sid_number_strings]
    sid_byte_array_str  = unsigned_number_to_slashed_byte_array_string(sid_numbers[0],       True,   2)
    sid_byte_array_str += unsigned_number_to_slashed_byte_array_string((dashes_count - 2),   True,   2)
    sid_byte_array_str += unsigned_number_to_slashed_byte_array_string(sid_numbers[1],       False, 12)
    sid_byte_array_str += unsigned_number_to_slashed_byte_array_string(sid_numbers[2],       True,   8)
    sid_byte_array_str += unsigned_number_to_slashed_byte_array_string(sid_numbers[3],       True,   8)
    sid_byte_array_str += unsigned_number_to_slashed_byte_array_string(sid_numbers[4],       True,   8)
    sid_byte_array_str += unsigned_number_to_slashed_byte_array_string(sid_numbers[5],       True,   8)
    return sid_byte_array_str

Answer 2

SID必须为二进制格式，然后尝试：

from ldap3 import Server, Connection, ALL
from ldap3.utils.conv import escape_bytes

s = Server('my_server', get_info=ALL)
c = Connection(s, 'my_user', 'my_password')
c.bind()

binary_sid = b'....'  # your sid must be in binary format

c.search('my_base', '(objectsid=' + escape_bytes(binary_sid) + ')', attributes=['objectsid', 'samaccountname'])
print(c.entries)

您应该在c.entries[0].sAMAccountName中获取帐户名