我正在用Python列表编程地建立一个plots列表,我想把它放到vplot
函数,而不是当前使用的grid
。文档中有子对象的显式枚举,但是我想知道是否可以获取一个figure对象的列表并将它们接收到vplot中,就像对grid对象所做的那样。在
channelPlots = []
for channel in myChannels :
channelPlot = figure( width=1000, height=1000 , title=channel+ " Time Series" , x_axis_label = channel , y_axis_label = "TIME" )
y = sample.data['TIME' ]
x = sample.data[channel]
channelPlot.scatter(x,y)
channelPlots.append(channelPlot)
# With a grid it works
#grid = GridPlot(children=[channelPlots], title="Time Series Channel Plots")
# with a vplot it breaks
grid = vplot( channelPlots )
save(grid)
Exception error is: expected an element of List(Instance(Widget)), got [[<bokeh.plotting.Figure object at 0x0000000009AA2128>, <bokeh.plotting.Figure object at 0x0000000006778CF8>, <bokeh.plotting.Figure object at 0
x0000000011894C50>, <bokeh.plotting.Figure object at 0x00000000118DE390>, <bokeh.plotting.Figure object at 0x00000000118DEF98>, <bokeh.plotting.Figure object at 0x00000000118F2668>, <bokeh.plotting.Figure object at
0x00000000118EE7B8>, <bokeh.plotting.Figure object at 0x00000000118EE630>]]
尝试下面两种方法都会引发相同的异常。。。在
^{pr2}$
您需要将列表显式地作为
children
参数传递:或者,
^{pr2}$vplot
接受子元素为*args
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