用Python抓取urbandictionary

Question

我现在正在研究一个arcbot，我正在尝试发出一个命令“！“urbandictionary”，它应该获取一个术语的含义，第一个是urbandictionary提供的，如果有其他解决方案，例如，另一个字典站点有一个更好的api，这也很好。我的代码是：

if Command.lower() == '!urban': 
    dictionary = Argument[1] #this is the term which the user provides, e.g. "scrape"
    dictionaryscrape = urllib2.urlopen('http://www.urbandictionary.com/define.php?term='+dictionary).read() #plain html of the site
    scraped = getBetweenHTML(dictionaryscrape, '<div class="meaning">','</div>') #Here's my problem, i'm not sure if it scrapes the first meaning or not..
    messages.main(scraped,xSock,BotID) #Sends the meaning of the provided word (Argument[0])

如何在urbandictionary中正确地提取单词的意思？在

Answer 1

只需从meaning类中获取text：

import  requests

from bs4 import BeautifulSoup
word = "scrape"
r = requests.get("http://www.urbandictionary.com/define.php?term={}".format(word))

soup = BeautifulSoup(r.content)

print(soup.find("div",attrs={"class":"meaning"}).text)

Gassing and breaking your car repeatedly really fast so that the front and rear bumpers "scrape" the pavement; while going hyphy 

Answer 2

这里显然有一个非官方的api

`http://api.urbandictionary.com/v0/define?term={word}`

来自https://github.com/zdict/zdict/wiki/Urban-dictionary-API-documentation