在Python OpenCV中创建流程图

Question

更新问题：

有人能给我指出任何可以帮助我用python绘制光流图的材料的方向吗？理想情况下，我想找到一个类似于这里显示的视频输出的东西：http://study.marearts.com/2014/04/opencv-study-calcopticalflowfarneback.html。或者有类似功能输出的东西

我已经实现了密集光流算法（cv2.calcOpticalFlowFarneback）。从这个角度，我可以在图像的特定点取样。 输入的视频源是640x480，我已经将采样点设置为垂直和水平每五个像素。在

import cv2
import numpy as np
import matplotlib.pyplot as plt

cap = cv2.VideoCapture("T5.avi")

ret, frame1 = cap.read()

prvs = cv2.cvtColor(frame1, cv2.COLOR_BGR2GRAY)
hsv = np.zeros_like(frame1)
hsv[..., 1] = 255

[R,C]=prvs.shape
count=0
while (1):
    ret, frame2 = cap.read()
    next = cv2.cvtColor(frame2, cv2.COLOR_BGR2GRAY)

    flow = cv2.calcOpticalFlowFarneback(prvs, next, None, 0.5, 3, 15, 2, 5, 1.2, 0)
    mag, ang = cv2.cartToPolar(flow[..., 0], flow[..., 1])

    RV=np.arange(5,480,5)
    CV=np.arange(5,640,5)
    # These give arrays of points to sample at increments of 5
    if count==0:
        count =1 #so that the following creation is only done once
        [Y,X]=np.meshgrid(CV,RV)
        # makes an x and y array of the points specified at sample increments

    temp =mag[np.ix_(RV,CV)]
    # this makes a temp array that stores the magnitude of flow at each of the sample points

    motionvectors=np.array((Y[:],X[:],Y[:]+temp.real[:],X[:]+temp.imag[:]))

    Ydist=motionvectors[0,:,:]- motionvectors[2,:,:]
    Xdist=motionvectors[1,:,:]- motionvectors[3,:,:]
    Xoriginal=X-Xdist
    Yoriginal=Y-Ydist



    plot2 = plt.figure()
    plt.quiver(Xoriginal, Yoriginal, X, Y,
               color='Teal',
               headlength=7)

    plt.title('Quiver Plot, Single Colour')
    plt.show(plot2)


    hsv[..., 0] = ang * 180 / np.pi / 2
    hsv[..., 2] = cv2.normalize(mag, None, 0, 255, cv2.NORM_MINMAX)
    bgr = cv2.cvtColor(hsv, cv2.COLOR_HSV2BGR)
    cv2.imshow('frame2', bgr)

    k = cv2.waitKey(30) & 0xff

    if k == 27:
        break
    prvs = next

cap.release()
cv2.destroyAllWindows()

我想我已经计算了像素的原始和最终的X，Y位置和移动的距离，并将它们放入matplotlib震颤图中。在

我得到的结果与稠密光流的hsv图（我知道这是正确的，因为它是从OpenCV教程中获取的）不一致，并且箭筒图每次只显示一个帧，在下一个显示之前必须退出该图。在

有人能看到我在计算中哪里出错了吗？我如何使绘图在每一帧中自动更新？在

Answer 1

我不知道如何改变matplotlib震颤图的行为，但我确信这是可能的。在

另一种方法是创建一个函数，根据计算的光流在原始图像的顶部绘制线。以下代码应实现这一点：

def dispOpticalFlow( Image,Flow,Divisor,name ):
"Display image with a visualisation of a flow over the top. A divisor controls the density of the quiver plot."
PictureShape = np.shape(Image)
#determine number of quiver points there will be
Imax = int(PictureShape[0]/Divisor)
Jmax = int(PictureShape[1]/Divisor)
#create a blank mask, on which lines will be drawn.
mask = np.zeros_like(Image)
for i in range(1, Imax):
  for j in range(1, Jmax):
     X1 = (i)*Divisor
     Y1 = (j)*Divisor
     X2 = int(X1 + Flow[X1,Y1,1])
     Y2 = int(Y1 + Flow[X1,Y1,0])
     X2 = np.clip(X2, 0, PictureShape[0])
     Y2 = np.clip(Y2, 0, PictureShape[1])
     #add all the lines to the mask
     mask = cv2.line(mask, (Y1,X1),(Y2,X2), [255, 255, 255], 1)
#superpose lines onto image
img = cv2.add(Image,mask)
#print image
cv2.imshow(name,img)
return []

这段代码只创建行而不是箭头，但是经过一些努力，它可以被修改为显示箭头。在