使用列表检查字符串是否包含某个字母或数字

Question

我要回答的问题需要你验证汽车牌照。它必须查找由两个字母、三个数字、三个字母组成的序列，否则将返回一个类似“无效邮政编码”的消息

我需要知道如何通过与列表比较来检查字符串是否包含某个字母或数字。在

到目前为止，我得到的是：

# Task 2

import random
import re

def regNumber():
    # Generate a Car Reg Number
    letters = ["A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"]
    numbers = ["1","2","3","4","5","6","7","8","9","0"]

    letter1 = random.choice(letters)
    letter2 = random.choice(letters)
    number1 = random.choice(numbers)
    number2 = random.choice(numbers)
    letter3 = random.choice(letters)
    letter4 = random.choice(letters)
    letter5 = random.choice(letters)
    licensePlate = (letter1 + letter2 + number1 + number2 + letter3 + letter4 + letter5)
    return licensePlate, letters, numbers

carReg, letters, numbers = regNumber()

print(carReg)
if letters not in carReg: print("Success")

但是，我得到一个错误：

^{pr2}$

感谢任何帮助。在

Answer 1

改变

if letters not in carReg: print("Success")

到

^{pr2}$

在你的代码中，你有一个字符串列表，这就是为什么我把你的if条件改为for循环，这样列表中的每个元素都会被检查是否出现在carReg string中。在

或者，我认为你应该用旗子来解决你的问题。是这样的：

flag = 0
for l in letters:
    if l in carReg: 
        flag = 1
        break

if flag == 0:
    print("Success")