擅长:python、mysql、java
<p>如果我正确理解您的问题,下面的代码将解决您的问题。在</p>
<pre><code> Count = dict()
for l in text:
words = l['reviews'].split()
for i in range(0,len(words) -1):
bigram = " ".join(words[i:i+2] )
if not bigram in Count:
Count[bigram] = 1;
else:
Count[bigram] = Count[bigram] + 1
</code></pre>
<p>计数为:</p>
^{pr2}$
<p>在编辑:如果你想用key作为元组只需改变连接线。python dict也散列元组。在</p>