擅长:python、mysql、java
<p>添加条件以仅添加具有足够vovel的单词</p>
<pre><code>def vowelCount(s):
vowels = 'aeiou'
countVowels = 0
for letter in s.lower():
if letter in vowels:
countVowels += 1
return countVowels
def manyVowels(t, i):
my_string = t.split()
my_dict = {}
for word in my_string:
number = vowelCount(word)
if number >= i:
my_dict[word] = number
return my_dict
</code></pre>
<p>行<code>my_dict[word] = number</code>将<code>vowelCount(word)</code>的结果添加到字典中。但前提是vovel数至少为<code>i</code>。在</p>