如何在python中不使用min函数，同时使用while循环从列表中查找最小值

Question

我对python有点陌生，最近遇到了一个我无法理解的问题，即如何在不使用python中的min或max函数的情况下找到列表的最小值。以下是我的代码：

#Prompt user to enter a minimum of 5 round trip times separated with commas
roundTrips = input('Please enter at least 5 round trips seprated by ",": ')



#Check closest object
def closest_object(roundTrips):
    roundTrips = list(roundTrips.split(','))
    count = 0
    minimum = 0
    if len(roundTrips)<=4:
        print('error')
    else:
        while count<len(roundTrips):
            positions = roundTrips[count]
            count += 1
            if minimum or (int(positions)<minimum):
                minimum = positions
                print(minimum)

    #Perform the parsing of roundTrips input here

    closestObject = []

    print('The closest object is',closestObject) #Modify to display the closest object

    return closestObject#Do not remove this line

Answer 1

lst = [10, 1,2,3,4,5]
ans = lst[0]
i=0
while(i<len(lst)):
    if lst[i] < ans:
        ans = lst[i]
    i+=1
print(ans)

这是可行的，但我不认为这样简单的任务，你需要问关于stackoverflow的问题。你可以在网上找到许多类似的答案