如何使用应用程序工厂正确设置Flask管理视图?

2024-06-02 19:17:12 发布

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我正在尝试根据“用户”和“角色”模型设置flask-admin model views with SQLAlchemy。我得到的不是函数管理视图:

ValueError: Invalid model property name <class 'app.models.Role'>.desc

堆栈跟踪:

^{pr2}$

我使用的是一个带有蓝图的烧瓶应用工厂方法。这是我的应用工厂。在

我的__init__.py文件,我尝试在第49行创建视图:

from flask import Flask
from flask.ext.bootstrap import Bootstrap
from flask.ext.mail import Mail
from flask.ext.moment import Moment
from flask.ext.sqlalchemy import SQLAlchemy
from flask.ext.security import Security
from flask.ext.admin import Admin
from flask_s3 import FlaskS3
from flask.ext.cdn import CDN
from flask.ext.assets import Environment
from flask.ext.assets import PythonLoader as PythonAssetsLoader
from config import config


# app setup
bootstrap = Bootstrap()
mail = Mail()
moment = Moment()
db = SQLAlchemy()
security = Security()
admin = Admin()
s3 = FlaskS3()
cdn = CDN()
assets_env = Environment()



def create_app(config_name):
  app = Flask(__name__)
  app.config.from_object(config[config_name])
  app.name = app.config['APP_NAME']
  config[config_name].init_app(app)

  from .models import user_datastore, User, Role
  from .auth.views import RoleAdmin, UserAdmin

  bootstrap.init_app(app)
  mail.init_app(app)
  moment.init_app(app)
  db.init_app(app)
  security.init_app(app, user_datastore)
  admin.init_app(app)
  s3.init_app(app)
  cdn.init_app(app)
  assets_env.init_app(app)

  # Here's where I'm trying to create the views
  admin.add_view(RoleAdmin(Role, db.session))
  admin.add_view(UserAdmin(User, db.session))

  from . import assets
  assets_loader = PythonAssetsLoader(assets)
  for name, bundle in assets_loader.load_bundles().iteritems():
    assets_env.register(name, bundle)

  # attach asset bundles, routes, and custom error pages here
  from main import main as main_blueprint
  app.register_blueprint(main_blueprint)
  import main.assets as main_assets
  assets_loader = PythonAssetsLoader(main_assets)
  for name, bundle in assets_loader.load_bundles().iteritems():
    assets_env.register(name, bundle)

  from auth import auth as auth_blueprint
  app.register_blueprint(auth_blueprint)


  return app

我的ModelView类:

from flask.ext.admin.contrib.sqla import ModelView

__author__ = 'dbg'

class RoleAdmin(ModelView):
  column_display_pk = True
  form_columns = ['id', 'desc']

class UserAdmin(ModelView):
  column_display_pk = True
  form_columns = ['id', 'email', 'active', 'last_login_at', 'login_count', 'roles']

编辑

Models.py

from app import db
from flask.ext.security import UserMixin, RoleMixin, SQLAlchemyUserDatastore


roles_users = db.Table('roles_users',
                       db.Column('user_id', db.Integer(), db.ForeignKey('user.id')),
                       db.Column('role_id', db.Integer(), db.ForeignKey('role.id')))


class Role(db.Model, RoleMixin):
  id = db.Column(db.Integer(), primary_key=True)
  name = db.Column(db.String(80), unique=True)
  description = db.Column(db.String(255))


class User(db.Model, UserMixin):
  id = db.Column(db.Integer(), primary_key=True)
  email = db.Column(db.String(256), unique=True)
  password = db.Column(db.String(36))
  active = db.Column(db.Boolean())
  confirmed_at = db.Column(db.DateTime())
  last_login_at = db.Column(db.DateTime())
  current_login_at = db.Column(db.DateTime())
  last_login_ip = db.Column(db.String(45))
  current_login_ip = db.Column(db.String(45))
  login_count = db.Column(db.Integer())
  roles = db.relationship('Role', secondary=roles_users,
                          backref=db.backref('users', lazy='dynamic'))


user_datastore = SQLAlchemyUserDatastore(db, User, Role)

更新

通过这个good soul找到了一个非常有用的here。还是卡住了。新错误。在

Traceback (most recent call last):
  File "/Users/dbg/Projects/Python/Current/ziff/flaskbase/manage.py", line 18, in <module>
    app = create_app(os.getenv('APP_CONFIG') or 'default')
  File "/Users/dbg/Projects/Python/Current/ziff/flaskbase/app/__init__.py", line 83, in create_app
    admin.add_view(RoleAdmin(RoleAdmin, db.session))
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 288, in __init__
    menu_icon_value=menu_icon_value)
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 570, in __init__
    self._refresh_cache()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 632, in _refresh_cache
    self._list_columns = self.get_list_columns()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/model/base.py", line 708, in get_list_columns
    columns = self.scaffold_list_columns()
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 371, in scaffold_list_columns
    for p in self._get_model_iterator():
  File "/usr/local/share/anaconda/envs/flaskbase27/lib/python2.7/site-packages/Flask_Admin-1.0.9-py2.7.egg/flask_admin/contrib/sqla/view.py", line 310, in _get_model_iterator
    return model._sa_class_manager.mapper.iterate_properties
AttributeError: type object 'RoleAdmin' has no attribute '_sa_class_manager'

Tags: nameinfrompyimportconfigappflask
2条回答

以下是使用蓝图的另一种方法:

# app/__init__.py

from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from flask_admin import Admin

db = SQLAlchemy()
admin = Admin(name='my-app', template_mode='bootstrap3')


def create_app():
    app = Flask(__name__)

    db.init_app(app)
    admin.init_app(app)

    # Add the admin panel
    from app.admin import bp as admin_bp
    app.register_blueprint(admin_bp)

    return app
^{pr2}$
# app/admin/routes.py

from flask_admin.contrib.sqla import ModelView
from app import db, admin
from app.models import City

admin.add_view(ModelView(City, db.session))

好吧,这很古老,但我是这样做的:

# Inside app/auth/__init__.py (auth module includes admin):

#...
from app import db
from flask import Blueprint
from .my_custom_model_views import MyModelView
from ..models import MyModel
#...
auth = Blueprint('auth', __name__)
from . import views
#...
auth.custom_model_views = []
auth.custom_model_views += [MyModelView(MyModel, db.session)]
#...
from . import forms

# Inside app/__init__.py
# ...
admin = Admin(name='Name', ...)
# ...
def create_app(config_name):
# ...
    app = Flask(__name__)
    # ...
    admin.init_app(app)
    # And here's the important part
    with app.app_context():
        from .auth import auth as auth_blueprint
        admin.add_views(*auth_blueprint.custom_model_views)

重要的部分是以某种方式存储您要添加的视图(这里,我只是将它们附加到蓝图中),然后使用APP CONTEXT添加它们。否则,一切都会变得疯狂(没有应用程序上下文,可能会多次添加同一个模型,导致在应用程序实例化期间出现难看的名称冲突错误)。在

值得注意的是,您在这里添加的任何视图都将显示在flask admin菜单中,就像它是一个模型视图一样,即使它是其他类型的视图。您可以通过更改视图的is-visible和is-unu-accessible方法来解决此问题。在

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