Python 3：搜索子目录中的文件

Question

我在Mac上用Pycharm。{{cdm>调用下面的cdm>}函数。它输出“文件存在”，因为dwnld.py位于脚本（/Users/BobSpanks/PycharmProjects/my scripts）的同一目录中。 如果我要将dwnld.py放在不同的位置，如何让下面的代码搜索从/Users/BobbySpanks开始的所有子目录中的dwnld.py？我试着看os.path笔记，但我真的找不到我需要的东西。我是Python新手。在

import os.path

File = "dwnld.py"

if os.path.isfile(File):
    print("File exists")
else:
    print("File doesn't exist")

Answer 1

这可能对您有用：

import os
File = 'dwnld.py'
for root, dirs, files in os.walk('/Users/BobbySpanks/'):  
    if File in files:
        print ("File exists")

---

os.walk(top, topdown=True, onerror=None, followlinks=False)

Generate the file names in a directory tree by walking the tree either top-down or bottom-up. For each directory in the tree rooted at directory top (including top itself), it yields a 3-tuple (dirpath, dirnames, filenames). _Source

Answer 2

试试这个

import os
File = "dwnld.py"

for root, dirs, files in os.walk('.'):
    for file in files: # loops through directories and files
        if file == File: # compares to your specified conditions
            print ("File exists")

取自：https://stackoverflow.com/a/31621120/5135450

Answer 3

您可以为此使用^{} module：

import glob
import os

pattern = '/Users/BobbySpanks/**/dwnld.py'

for fname in glob.glob(pattern, recursive=True):
    if os.path.isfile(fname):
        print(fname)

未检查dwnld.py是否为文件的简化版本：

^{pr2}$

理论上，它现在可能是一个目录。在

If recursive is true, the pattern '**' will match any files and zero or more directories and subdirectories.