Python正则表达式：替换后跟空格的点和符号

Question

我想替换dot/？/ ! 后跟空格（如果有）到特征线字符\n，并消除空白。 所以对于：hello world. It's nice.我希望它是hello world.\nIt'snice.\n
这就是我所想的（但它行不通，否则我就不会写这个问题了哈？）在

re.sub(r'\.!?( *)', r'.\n\1', line)

谢谢！在

Answer 1

将空格或字符串的结尾与后面的正视图匹配：

re.sub(r'(?<=[.?!])( +|\Z)', r'\n', text)

因为这只匹配前面有标点符号的空格，所以不需要使用反向引用。在

+确保此处只匹配后跟空格的标点符号。正文：

^{pr2}$

否则会收到太多的新行。在

演示：

>>> import re
>>> text = "hello world. It's nice."
>>> re.sub(r'(?<=[.?!])( +|\Z)', r'\n', text)
"hello world.\nIt's nice.\n"
>>> text = "His thoughts trailed away... His heart wasn't in it!"
>>> re.sub(r'(?<=[.?!])( +|$)', r'\n', text)
"His thoughts trailed away...\nHis heart wasn't in it!\n"

Answer 2

无需环顾：

>>> import re
>>> line="hello world! What? It's nice."
>>> re.sub(r'([.?!]+) *', r'\1\n', line)   # Capture punctuations; discard spaces
"hello world!\nWhat?\nIt's nice.\n"

>>> line="hello world! His thoughts trailed away... What?"
>>> re.sub(r'([.?!]+) *', r'\1\n', line)
'hello world!\nHis thoughts trailed away...\nWhat?\n'

Answer 3

你试过replace？在

print text.replace('. ','.\n').replace('? ','?\n').replace('! ','!\n')