使用Python OpenCV在循环中平铺图像

Question

Python noob需要帮助！有人能告诉我如何用循环重写代码吗？尝试了一些不同的语法，但似乎不起作用！在

img = cv2.imread("C://Users//user//Desktop//research//images//Underwater_Caustics//set1//set1_color_0001.png")

    tile11=img[1:640, 1:360]
    cv2.imwrite('tile11_underwater_caustic_set1_0001.png', tile11)

    tile12=img[641:1280, 1:360]
    cv2.imwrite('tile12_underwater_caustic_set1_0001.png', tile12)

    tile13=img[1281:1920, 1:360]
    cv2.imwrite('tile13_underwater_caustic_set1_0001.png', tile13)

    tile21=img[1:640, 361:720]
    cv2.imwrite('tile21_underwater_caustic_set1_0001.png', tile21)

    tile22=img[641:1280, 361:720]
    cv2.imwrite('tile22_underwater_caustic_set1_0001.png', tile22)

    tile23=img[1281:1920, 361:720]
    cv2.imwrite('tile23_underwater_caustic_set1_0001.png', tile23)

    tile31=img[1:640, 721:1080]
    cv2.imwrite('tile31_underwater_caustic_set1_0001.png', tile31)

    tile32=img[641:1280, 721:1080]
    cv2.imwrite('tile32_underwater_caustic_set1_0001.png', tile32)

    tile33=img[1281:1920, 721:1080]
    cv2.imwrite('tile33_underwater_caustic_set1_0001.png', tile33)

如您所见，图像将被切成9个大小相等的块，如何使用循环来编写它？在

Answer 1

这不会产生与代码相同的结果，但会给您一些想法：

img = cv2.imread('sample.jpg')
numrows, numcols = 4, 4
height = int(img.shape[0] / numrows)
width = int(img.shape[1] / numcols)
for row in range(numrows):
    for col in range(numcols):
        y0 = row * height
        y1 = y0 + height
        x0 = col * width
        x1 = x0 + width
        cv2.imwrite('tile_%d%d.jpg' % (row, col), img[y0:y1, x0:x1])