Pythonjson.loads（）返回jsondecode

Question

youtube给了我很多想要的直播节目。为此，我使用了google的api，它在json文件中提供信息：

{
 "kind": "youtube#channelListResponse",
 "etag": "\"XI7nbFXulYBIpL0ayR_gDh3eu1k/wTcrqM2kHwjf7GxOEpSBk_lofRA\"",
 "pageInfo": {
  "totalResults": 1,
  "resultsPerPage": 5
 },
 "items": [
  {
   "kind": "youtube#channel",
   "etag": "\"XI7nbFXulYBIpL0ayR_gDh3eu1k/HhHZCWV2vASrbydwK9ItUgUm0X8\"",
   "id": "UC-lHJZR3Gqxm24_Vd_AJ5Yw",
   "statistics": {
    "viewCount": "19893639729",
    "commentCount": "0",
    "subscriberCount": "79695778",
    "hiddenSubscriberCount": false,
    "videoCount": "3707"
   }
  }
 ]
}

代码如下：

^{pr2}$

但是当我试图用json.loads（），我得到以下错误：

json.decoder.JSONDecodeError: Expecting property name enclosed in double quotes: line 2 column 2 (char 3)

同时：

print(ascii(json_str))
'{\n {\n "kind": "youtube#channelListResponse",\n "etag": ""XI7nbFXulYBIpL0ayR_gDh3eu1k/wTcrqM2kHwjf7GxOEpSBk_lofRA"",\n "pageInfo": {\n  "totalResults": 1,\n  "resultsPerPage": 5\n },\n "items": [\n  {\n   "kind": "youtube#channel",\n   "etag": ""XI7nbFXulYBIpL0ayR_gDh3eu1k/HhHZCWV2vASrbydwK9ItUgUm0X8"",\n   "id": "UC-lHJZR3Gqxm24_Vd_AJ5Yw",\n   "statistics": {\n    "viewCount": "19893639729",\n    "commentCount": "0",\n    "subscriberCount": "79695778",\n    "hiddenSubscriberCount": false,\n    "videoCount": "3707"\n   }\n  }\n ]\n}\n'

是什么引起的问题？在

Answer 1

使用下面的代码，我可以打开您的JSON并打印它。将JSON保存到临时json试试这个：

import json

with open("temp.json", "r") as infile:
    data = json.loads(infile.read())

print(data)