尝试从函数返回布尔值

Question

我试图编程一个简单的基于文本的游戏。为了做到这一点，我让用户去三个不同的房间完成一项任务并收到一份。为了做到这一点，我将一个值设置为False，然后，在完成房间之后，我有一个return语句，用于将布尔值更改为True。当所有三个room函数都返回一个True时，我将其设置为打开一个进行游戏的函数。但是，正如所知，返回不会发生，因此布尔值保持不变。 以下是单门功能的示例：

def door1(incomp1):
    if incomp1 == False:
        print 'You enter door 1 and find a hideous internet troll.'
        print "The troll says, 'LOOK AT THIS LOSER'"
        options = ["YOU'RE THE LOSER", "I don't care." , "YOUR MOM IS FAT"]
        options2 = [1,2,3]
        for x in options:
            print "\t :> %s" % x
        choice1 = raw_input("What is your response? :>")
        if ('loser' in choice1) or ('fat' in choice1):
            print "You are sucked into the troll's behaviour and are driven insane"
            print "After three days of insanity, you starve to death"
            dead()
        elif 'care' in choice1:
            print 'The troll cannot feed off of your anger.'
            print 'The troll starves and you recover one piece of the lever from his stomach.'
            change()
            entrywayopen()
            return incomp1 == True
        else:
            unknown()
            change()
            door1(incomp1)
    elif incomp1 == True:
        print 'You already recovered the piece from room 1.'
        entrywayopen()

因此，当函数被调用时，incomp1的值已经是False。用户必须得到正确的答案，在本例中是elif语句。最后，我让它return incomp1 == True。然而，这个价值没有改变。我在这个房间的策略的最后一步是为语句if door1(incomp1) and door2(incomp2) and door3(incomp3):返回一个True的值。是什么原因导致值中的布尔值更改不被返回？在

Answer 1

关于Python布尔表达式：

• 每个python表达式都可以计算为布尔值
• None，False，0，0.0，空字符串、列表、元组和字典是False；其他大多数对象是True
• 这意味着：您通常只需编写x，而不是x == True，在您的例子中：if incomp1:

如果您正在执行一个函数，并且它没有命中return，那么None将被隐式返回。如果对它进行布尔比较，它的值将为False。在

Answer 2

您需要将“return incomp1==True”替换为“return True”。然后像这样调用door1函数“incomp1=door1（incomp1）”。 这将把incomp1的值更改为函数“True”返回的值。在

也可以用简单的“else”替换“elif incomp1==True:”。在

您还可以考虑将.lower（）添加到choice1=raw_input（“您的响应是什么？：>；“）。这样一来，如果玩家在输入中使用一个大写字母，它仍然可以按需要工作。在

def door1(incomp1):
    if incomp1 == False:
        print 'You enter door 1 and find a hideous internet troll.'
        print "The troll says, 'LOOK AT THIS LOSER'"
        options = ["YOU'RE THE LOSER", "I don't care." , "YOUR MOM IS FAT"]
        options2 = [1,2,3]
        for x in options:
            print "\t :> %s" % x
        #choice1 = raw_input("What is your response? :>")
        choice1 = raw_input("What is your response? :>").lower()
        if ('loser' in choice1) or ('fat' in choice1):
            print "You are sucked into the troll's behaviour and are driven insane"
            print "After three days of insanity, you starve to death"
            dead()
        elif 'care' in choice1:
            print 'The troll cannot feed off of your anger.'
            print 'The troll starves and you recover one piece of the lever from his stomach.'
            change()
            entrywayopen()
            return True
        else:
            unknown()
            change()
            door1(incomp1)
    #elif incomp1 == True:
    else:
        print 'You already recovered the piece from room 1.'
        entrywayopen()

incomp1 = door1(incomp1)