擅长:python、mysql、java
<p>以下是基于regex的方法:</p>
<pre><code># the replace function concatenates the two matches after
# converting them from hex to ascii
repfunc = lambda m: chr(int(m.group(1), 16))+chr(int(m.group(2), 16))
# the last parameter is the text you want to convert
result = re.sub('%u(..)(..)', repfunc, '%u616f')
print result
</code></pre>
<p>给予</p>
^{pr2}$