擅长:python、mysql、java
<p>不确定是否有直接的方法。但是,您可以使用这个小代码片段来实现您所追求的目标:</p>
<pre><code>all=[
"jaeger.jaeger-span.jaeger-ell.spam 385062 1583408544",
"jaeger.jaeger-span.jaeger-ell.FindTraces 385062 1583408544",
"jaeger.jaeger-span.jaeger-query.FindTraces 70681 1583386032",
"jaeger.jaeger-span.jaeger-on.GetOperations 5177 1583376432",
"jaeger.jaeger-span.jaeger-http.GetServices 5528 1583376528"
]
dic = {}
for str in all:
key = str.split(" ")[0].split(".")[-1]
dic[key]=str
sorted_keys = list(dic.keys())
sorted_keys.sort()
sorted_list = []
for key in sorted_keys:
sorted_list.append(dic[key])
print(sorted_list)
</code></pre>