显示Python字典中查询文件中每行单词的次数

Question

我有一个docs.txt文件，其中包含以下三行：

joyously urgently truthfully seemingly broadly urgently knowingly urgently steadily
joyously urgently truthfully seemingly rigidly broadly rigidly suddenly healthily commonly often
tremendously totally steadily sharply totally

我有一个querys.txt文件，其中包含：

urgently
rigidly suddenly
totally steadily

以及守则：

dictionary = {}
    angledictionary={}
    document= open('docs.txt', 'r')
    for line in document:
        lined=line.split()
        for word in lined:
            if word not in dictionary.keys():
                dictionary[word]=0
            dictionary[word]+=1
    dictionary=dict.fromkeys(dictionary,0)
    with open("queries.txt", "r") as open_queries:
        searchquery = open_queries.read().split("\n")
    with open('docs.txt', 'r') as openrelevancy:
        words = openrelevancy.read().split("\n")
    for query in searchquery:
        print('Query:', query)
        relevant = []
        line_number = 0
        for word in words:
            line_number += 1
            if query in word:
                relevant.append(line_number)
        print('Relevant Documents:', *relevant)

现在，每行的字典字数为0，我正在尝试这样做： 对于第1行：

{'joyously': 1, 'urgently': 3, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 1, 'steadily': 1, 'rigidly': 0, 'suddenly': 0, 'healthily': 0, 'commonly': 0, 'often': 0, 'tremendously': 0, 'totally': 0, 'sharply': 0}

第2行：

{'joyously': 1, 'urgently': 1, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 1, 'steadily': 1, 'rigidly': 2, 'suddenly': 1, 'healthily': 1, 'commonly': 1, 'often': 1, 'tremendously': 0, 'totally': 0, 'sharply': 0}

第3行：

{'joyously': 0, 'urgently': 0, 'truthfully': 0, 'seemingly': 0, 'broadly': 0, 'knowingly': 0, 'steadily': 0, 'rigidly': 0, 'suddenly': 0, 'healthily': 0, 'commonly': 0, 'often': 0, 'tremendously': 1, 'totally': 2, 'sharply': 1}

我怎样才能解决这个问题

Answer 1

一个简单的方法是使用collections.Counter：

from collections import Counter

with open("file.txt","r") as f:
    lineList = f.readlines()
for i,k in enumerate(map(lambda x:x.strip().split(" "),lineList)): # split each word
    print(f"Line {i+1}:{Counter(k)}")

结果:

Line 1:Counter({'urgently': 3, 'joyously': 1, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 1, 'steadily': 1})
Line 2:Counter({'rigidly': 2, 'joyously': 1, 'urgently': 1, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'suddenly': 1, 'healthily': 1, 'commonly': 1, 'often': 1})
Line 3:Counter({'totally': 2, 'tremendously': 1, 'steadily': 1, 'sharply': 1})

---

或者你可以用口述：

l = ['joyously', 'urgently', 'truthfully', 'seemingly', 'broadly', 'knowingly', 'steadily', 'rigidly', 'suddenly', 'healthily', 'commonly', 'often', 'tremendously', 'totally', 'sharply']
with open("file.txt","r") as f:
    lineList = f.readlines()

for line,i in enumerate(map(lambda x:x.strip().split(" "),lineList)):
    d = dict.fromkeys(l, 0) # load a dict from the list
    for j in i:
        d[j] += 1
    print(f"For line {line+1}:{d}")

结果:

For line 1:{'joyously': 1, 'urgently': 3, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 1, 'steadily': 1, 'rigidly': 0, 'suddenly': 0, 'healthily': 0, 'commonly': 0, 'often': 0, 'tremendously': 0, 'totally': 0, 'sharply': 0}
For line 2:{'joyously': 1, 'urgently': 1, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 0, 'steadily': 0, 'rigidly': 2, 'suddenly': 1, 'healthily': 1, 'commonly': 1, 'often': 1, 'tremendously': 0, 'totally': 0, 'sharply': 0}
For line 3:{'joyously': 0, 'urgently': 0, 'truthfully': 0, 'seemingly': 0, 'broadly': 0, 'knowingly': 0, 'steadily': 1, 'rigidly': 0, 'suddenly': 0, 'healthily': 0, 'commonly': 0, 'often': 0, 'tremendously': 1, 'totally': 2, 'sharply': 1}