如何在python函数中获得异步值？

Question

async def fun():
     return {id:1}


async def fun2():
     var=await fun()
     print(var.id)
     
fun2()

#输出：<；0x7faad2f70640处的协同路由对象fun2>

我只想得到fun2中的id值，请解释一下我应该怎么做

Answer 1

import asyncio
async def fun():
    return {'_id':1}


async def fun2():
    var = await fun()
    print(var)

asyncio.run(fun2())