回答此问题可获得 20 贡献值,回答如果被采纳可获得 50 分。
<p>我有以下数据帧,称为pop_df:</p>
<pre><code>pop_df
Out[33]:
2014 2015 2016 2017 2018 2019
Geo
AL 2892394.0 2885796.0 2875592.0 2876591.0 2870324.0 2862427.0
AL0 2892394.0 2885796.0 2875592.0 2876591.0 2870324.0 2862427.0
AL01 844921.0 836448.0 830981.0 826904.0 819793.0 813758.0
AL011 134332.0 131054.0 129056.0 125579.0 120978.0 118948.0
AL012 276058.0 277989.0 280205.0 284823.0 289626.0 290126.0
... ... ... ... ... ...
UKN12 142028.0 142756.0 143363.0 143746.0 144105.0 144367.0
UKN13 139774.0 140222.0 140752.0 141368.0 141994.0 142565.0
UKN14 137722.0 139426.0 140691.0 141917.0 143286.0 144771.0
UKN15 136332.0 136904.0 137492.0 138000.0 138441.0 138948.0
UKN16 114696.0 115171.0 115581.0 116057.0 116612.0 117051.0
[2034 rows x 6 columns]
</code></pre>
<p>我还有一份欧盟国家代码清单:</p>
<pre><code>EuropeanUnion=["BE","BG","CZ","DK","DE","EE","IE","EL","ES","FR","HR","IT","CY","LV","LT","LU","HU","MT","NL","AT","PL","PT","RO","SI","SK","FI","SE"]
</code></pre>
<p>我想过滤数据框,只保留列表中国家代码开头的行。我试过使用<code>pop_df.index.str.startswith</code>,但没能成功。如果你能提供帮助,我将不胜感激。提前谢谢</p>