擅长:python、mysql、java
<p>如本文所述,您并没有脱离外部循环:</p>
<pre><code>a = [[1,2,3], [4,5,6], [7,8,9], [1,4,7], [2,5,8], [3,6,9], [1,5,9], [7,5,3]]
b = [[9], [9, 7], [9, 7, 8], [9, 7, 8, 2]]
countdata = []
inner_break = False
for x in range(len(b)):
if inner_break:
break
for y in range(len(a)):
if all(elem in b[x] for elem in a[y]) == True:
inner_break = True
break
countdata.append(all(elem in b[x] for elem in a[y]))
print(len(countdata))
</code></pre>