如何在python列表中向带有字母的字符串添加标签？

Question

我写了一些代码，工作得很好，但我想让它更精确

其想法是添加一个字母，显示列表中元素的出现情况。初始列表如下所示

['1','2','1','2','1']

我想要

['1a','2a','1b','2b','1c']

我确信有一个快速的答案或功能可以做到这一点，有人有想法吗？

我的代码如下：

ancestrals = ['1','2','1','2','1']
uni_a = list(set(ancestrals))
for i in range(len(ancestrals)):
    tmp = uni_a.index(ancestrals[i])
    if uni_a[tmp][-1].isalpha():
        val = ancestrals[i][:1] + chr(ord(uni_a[tmp][-1])+1)
    else:
        val = ancestrals[i] + "a"

    ancestrals[i] = val

    while uni_a[tmp] in ancestrals[i:]:
        p = ancestrals[i:].index(uni_a[tmp])+ i
        ancestrals[p] = val

    uni_a[tmp] = ancestrals[i]
print(ancestrals)

Answer 1

ancestrals = ['1','2','1','2','1']

count = {}
for i, anc in enumerate(ancestrals):
    cnt = count.get(anc, 0)
    count[anc] = cnt + 1
    ancestrals[i] += chr(ord('a') + cnt)

print (ancestrals)
#  > ['1a', '2a', '1b', '2b', '1c']

当然，只有当每个元素的最大计数为26（字母“z”）时，这才有效