我在vba中使用以下宏在solidworks中制作零件。我有一个问题,从python我是否可以执行宏,而不必转到solidworks并从那里执行它
我试着寻找信息,但没有发现我在寻找什么
如果有人能帮助我,我将不胜感激
Dim swApp As SldWorks.SldWorks
Dim swDoc As SldWorks.ModelDoc2
Dim BoolStatus As Boolean
Dim swSketchManager As SldWorks.SketchManager
Dim longstatus As Long, longwarnings As Long
Dim Part As Object
Sub Main()
Set swApp = Application.SldWorks
Dim defaultTemplate As String
defaultTemplate = swApp.GetUserPreferenceStringValue(swUserPreferenceStringValue_e.swDefaultTemplatePart)
Set swDoc = swApp.NewDocument(defaultTemplate, 0, 0, 0)
BoolStatus = swDoc.Extension.SelectByID2("Front", "PLANE", 0, 0, 0, False, 0, Nothing, swSelectOption_e.swSelectOptionDefault)
Set swSketchManager = swDoc.SketchManager
Dim mySketchSegment As SldWorks.SketchSegment
swSketchManager.InsertSketch True
Set mySketchSegment = swSketchManager.CreateLine(0, 0, 0, 0, 1, 0)
Set mySketchSegment = swSketchManager.CreateLine(0, 1, 0, 2, 1, 0)
Set mySketchSegment = swSketchManager.CreateLine(2, 1, 0, 2, 2, 0)
Set mySketchSegment = swSketchManager.CreateLine(2, 2, 0, 4, 2, 0)
Set mySketchSegment = swSketchManager.CreateLine(4, 2, 0, 4, 1, 0)
Set mySketchSegment = swSketchManager.CreateLine(4, 1, 0, 6, 1, 0)
Set mySketchSegment = swSketchManager.CreateLine(6, 1, 0, 6, 0, 0)
Set mySketchSegment = swSketchManager.CreateLine(0, 0, 0, 6, 0, 0)
swDoc.ClearSelection2 True
Set Part = swApp.ActiveDoc
' Named View
Part.ShowNamedView2 "*Trimétrica", 8
Part.ViewZoomtofit2
BoolStatus = Part.Extension.SelectByID2("Line8", "SKETCHSEGMENT", 2.27939213179474, 0.424565217882254, 0.640103542052883, True, 0, Nothing, 0)
Part.ClearSelection2 True
BoolStatus = Part.Extension.SelectByID2("Line8", "SKETCHSEGMENT", 2.27939213179474, 0.424565217882254, 0.640103542052883, False, 16, Nothing, 0)
Dim myFeature As Object
Set myFeature = Part.FeatureManager.FeatureRevolve2(True, True, False, False, False, False, 0, 0, 6.2831853071796, 0, False, False, 0.01, 0.01, 0, 0, 0, True, True, True)
Part.SelectionManager.EnableContourSelection = False
Part.SetPickMode
Part.ClearSelection2 True
End Sub
目前没有回答
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