基于对另一列的计算创建列

2024-07-04 07:32:16 发布

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我想根据前一周的销售额创建另一个专栏。以下是示例输入:

df = pd.DataFrame({'Week':[1,1,2,2,3,3,4,4,5,5,1,1,2,2,3,3,4,4,5,5],
                   'Category':['Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White'],
                   'id':[1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2],
                   'Sales':[100,200,300,400,100,200,300,400,100,200,100,200,300,400,100,200,300,400,100,200],
                  'Sales_others':[10,20,30,40,10,20,30,40,10,20,10,20,30,40,10,20,30,40,10,20]})
print(df)

基于此,我想创建另一个专栏,它只不过是前一周的销售额。下面是所需输出的示例

    df_output = pd.DataFrame({'Week':[1,1,2,2,3,3,4,4,5,5,1,1,2,2,3,3,4,4,5,5],
                       'Category':['Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White','Red','White'],
                       'id':[1,1,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,2,2],
                       'Sales':[100,200,300,400,100,200,300,400,100,200,100,200,300,400,100,200,300,400,100,200],
                      'Sales_others':[10,20,30,40,10,20,30,40,10,20,10,20,30,40,10,20,30,40,10,20],
                      'Sales_previous_week':[0,0,100,200,300,400,100,200,300,400,0,0,100,200,300,400,100,200,300,400]})
print(df_output)

我发现很难创建一个自我连接。前一周应该只受销售文件的影响,我应该能够保留“sales_others”列

--编辑 添加原始代码

CR_UK_NL_Weeklevel['PREVIOUS_WEEK'] = CR_UK_NL_Weeklevel.groupby(['RETAIL_SITE_ID','CATEGORY_NAME'])['CURRENT_WEEK'].shift(fill_value=0)
print(CR_UK_NL_Weeklevel)

重命名列

CR_UK_NL_Weeklevel.columns.values[4] = 'CURRENT_WEEK'
CR_UK_NL_Weeklevel.columns.values[3] = 'LAST_YEAR_WEEK'
CR_UK_NL_Weeklevel.columns.values

正在尝试实施解决方案:

CR_UK_NL_Weeklevel['PREVIOUS_WEEK'] = CR_UK_NL_Weeklevel.groupby(['RETAIL_SITE_ID','CATEGORY_NAME'])['CURRENT_WEEK'].shift(fill_value=0)
print(CR_UK_NL_Weeklevel)

[78]:

CR_UK_NL_Weeklevel['PREVIOUS_WEEK'] = CR_UK_NL_Weeklevel.groupby(['RETAIL_SITE_ID','CATEGORY_NAME'])['CURRENT_WEEK'].shift(fill_value=0)
print(CR_UK_NL_Weeklevel)

--错误

--------------------------------------------------------------------------- KeyError回溯(最近一次呼叫最后一次) 在里面 ----&燃气轮机;1 CR_UK_NL_Weeklevel[‘上一周’]=CR_UK_NL_Weeklevel.groupby([‘零售网站ID’、‘类别名称’)[‘当前周’)。班次(填充值=0) 2份印刷品(CR_UK_NL_Weeklevel) getitem中的~\AppData\Local\Continuum\anaconda3\lib\site packages\pandas\core\base.py(self,key) 273其他: 274如果钥匙不在self.obj中: --&燃气轮机;275 raise KeyError(“未找到列:{key}”。格式(key=key)) 276返回自项目(键,ndim=1) 277 KeyError:“未找到列:当前_周”


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1条回答
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1楼 · 发布于 2024-07-04 07:32:16

如果每周和连续几周总是有相同的类别,请使用^{}Category列分组:

df['Sales_PREVIOUS'] = df.groupby('Category')['Sales'].shift(fill_value=0)
print (df)
   Week Category  Sales  Sales_PREVIOUS
0     1      Red    100               0
1     1    White    200               0
2     2      Red    300             100
3     2    White    400             200
4     3      Red    100             300
5     3    White    200             400
6     4      Red    300             100
7     4    White    400             200
8     5      Red    100             300
9     5    White    200             400

旋转的另一个想法是使用^{},然后使用^{}^{}表示Series,最后通过^{}添加新列:

s = df.pivot('Week','Category','Sales').shift(fill_value=0).stack()
df = df.join(s.rename('Sales_PREVIOUS WEEK'), on=['Week','Category'])

编辑:

使用新数据添加列id

df['Sales_PREVIOUS'] = df.groupby(['id','Category'])['Sales'].shift(fill_value=0)

对于第二种解决方案:

s = df.set_index(['Week','id','Category'])['Sales'].unstack([1,2]).shift(fill_value=0).unstack()
df = df.join(s.rename('Sales_PREVIOUS WEEK'), on=['id','Category','Week'])
print (df)
    Week Category  id  Sales  Sales_others  Sales_PREVIOUS WEEK
0      1      Red   1    100            10                    0
1      1    White   1    200            20                    0
2      2      Red   1    300            30                  100
3      2    White   1    400            40                  200
4      3      Red   1    100            10                  300
5      3    White   1    200            20                  400
6      4      Red   1    300            30                  100
7      4    White   1    400            40                  200
8      5      Red   1    100            10                  300
9      5    White   1    200            20                  400
10     1      Red   2    100            10                    0
11     1    White   2    200            20                    0
12     2      Red   2    300            30                  100
13     2    White   2    400            40                  200
14     3      Red   2    100            10                  300
15     3    White   2    200            20                  400
16     4      Red   2    300            30                  100
17     4    White   2    400            40                  200
18     5      Red   2    100            10                  300
19     5    White   2    200            20                  400

编辑:

列名称存在问题,请使用:

cols = CR_UK_NL_Weeklevel.columns.tolist()
cols[4] = 'CURRENT_WEEK'
cols[3] = 'LAST_YEAR_WEEK'
CR_UK_NL_Weeklevel.columns = cols

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